inates, Sically. *2.5.9. Solve Laplace's equation inside a 90° sector of a circular annulus (a
Posted: Sat Feb 26, 2022 10:52 am
inates, Sically. *2.5.9. Solve Laplace's equation inside a 90° sector of a circular annulus (a <r <b, 0< 0 < 7/2) subject to the boundary conditions (Hint: In polar coordinates, a ди 1 a r ar 1 U = r- ar p2 202 = 0, ]: 7= ² u = in 1 2²u To co ) + Solbadevi it is known that if u(r,0) = $(0) G(r), then & de Cr ) = -40 DO (a) u(r,0) = 0, ur, 7/2) = 0, u(a,0) = 0, u(6,0) = f(0) (b) u(r,0) = 0, u(r, 7/2) = f(r), u(a,0) = 0, u(6,0) = 0 1 dG dr = G do2.): DO - = =
Posted: Sat Feb 26, 2022 10:52 am
inates, Sically. *2.5.9. Solve Laplace's equation inside a 90° sector of a circular annulus (a <r <b, 0< 0 < 7/2) subject to the boundary conditions (Hint: In polar coordinates, a ди 1 a r ar 1 U = r- ar p2 202 = 0, ]: 7= ² u = in 1 2²u To co ) + Solbadevi it is known that if u(r,0) = $(0) G(r), then & de Cr ) = -40 DO (a) u(r,0) = 0, ur, 7/2) = 0, u(a,0) = 0, u(6,0) = f(0) (b) u(r,0) = 0, u(r, 7/2) = f(r), u(a,0) = 0, u(6,0) = 0 1 dG dr = G do2.): DO - = =