Use the direct-design method to compute the moments for the column-strip and middle-strip spanning perpendicular to the
Posted: Sat Feb 19, 2022 3:15 pm
Use the direct-design method to compute the moments for the
column-strip and middle-strip spanning perpendicular to the edge of
the exterior bay of the flat-plate shown in the figure below.
Assume the slab is 7.5 in. thick and supports a superimposed dead
load of 25 psf and a live load of 50 psf. There is no edge beam.
The columns are all 18 in. square
3) Use the direct-design method to compute the moments for the column-strip and middle-strip spanning perpendicular to the edge of the exterior bay of the flat-plate shown in the figure below. Assume the slab is 7.5 in. thick and supports a superimposed dead load of 25 psf and a live load of 50 psf. There is no edge beam. The columns are all 18 in. square. 19 ft 0 in. 19 ft 0 in. Edge 9 in. 20 ft 0 in. All columns 18 in. by 18 in. Some solutions: Mo = 181 kip-ft, interior middle-strip neg. moment = -32 kip-ft, column- strip positive moment = 56 kip-ft
column-strip and middle-strip spanning perpendicular to the edge of
the exterior bay of the flat-plate shown in the figure below.
Assume the slab is 7.5 in. thick and supports a superimposed dead
load of 25 psf and a live load of 50 psf. There is no edge beam.
The columns are all 18 in. square
3) Use the direct-design method to compute the moments for the column-strip and middle-strip spanning perpendicular to the edge of the exterior bay of the flat-plate shown in the figure below. Assume the slab is 7.5 in. thick and supports a superimposed dead load of 25 psf and a live load of 50 psf. There is no edge beam. The columns are all 18 in. square. 19 ft 0 in. 19 ft 0 in. Edge 9 in. 20 ft 0 in. All columns 18 in. by 18 in. Some solutions: Mo = 181 kip-ft, interior middle-strip neg. moment = -32 kip-ft, column- strip positive moment = 56 kip-ft