Answer Happy

STEPS 1. Find the mean of the probability distribution. 2. Subtract the mean from each value of the random variable x. 3. Square the results obtained in Step 2. 4. Multiply the results obtained in Step 3 by the corresponding probability. 5. Get the sum of the results obtained in Step 4 2 Given the probability mass function, solve for the mean and variance. х х P(x) x*P(x) XU X- (x-w) 4 P(x)*(x-w) 1 0.16 0.16 -1.94 3.7636 0.602176 2 0.22 0.44 -0.94 0.8836 0.194392 3 0.28 0.84 0.06 0.0036 0.001008 4 0.20 0.80 1.06 1.1236 0.224720 5 0.14 0.70 2.06 4.2436 0.594104 Z(X-u) P(x)=1.6164 H= 2.94 Therefore, the mean is 2.94 and the variance is 1.6164. Learning Module in Statistics and Probabllity Situation: A company tracks the number of sales new employees make each day during a 100-day probationary period. The results for one new employee are shown below. Find the variance of the probability distribution Sales per day (x) 0 1 2 3 4 5 6 6 7 7 Number of days (6) 16 19 15 21 9 10 8 2 C. ACTIVITY 1. Complete the table below х P(x) X*P(x) X-P (x-1) P(x)*(x-1) 0 0 1 2 3 4 5 6