Question 16 4 pts Suppose we were not told that 20% of M&Ms are blue by the company, but instead want to estimate this p
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Question 16 4 pts Suppose we were not told that 20% of M&Ms are blue by the company, but instead want to estimate this p
Question 16 4 pts Suppose we were not told that 20% of M&Ms are blue by the company, but instead want to estimate this population proportion through a confidence interval. Taking a sample of 100 M&Ms, 19% of them were blue. Using a 95% confidence level, what is the margin of error on the estimate of 19%? Round to three decimal places. 0.031 0.027 0.101 0,065