Question 9 (1 point) ✓ Saved If 5.27 moles of copper(II) sulfide and 6.93 moles of nitric acid are mixed, how many moles
Posted: Sun Feb 13, 2022 8:03 am
Question 9 (1 point) ✓ Saved If 5.27 moles of copper(II) sulfide and 6.93 moles of nitric acid are mixed, how many moles of NO(g) are produced? The equation for the reaction is 3CuS(s) + 8HNO3(aq) ---> 3Cu(NO3)2(aq) + 2NO(g) + 3S(s) + 4H2O(1) > Enter only the numerical answer, to the correct number of significant figures. Your Answer: 1.73 Your Answer