Three events occur with probabilities P(E.) 0.33, P (2) - 011, and P(Ex) - 043. If the event occurs, the probability bec
Posted: Sun Sep 05, 2021 5:15 pm
Three events occur with probabilities P(E.) 0.33, P (2) - 011, and P(Ex) - 043. If the event occurs, the probability becomes P(6,1) 0.21. P(B) = 0.29. Complete parts a through c. a. Calculate P(E, and B) b. Compute P(E or B) c. Assume that E. Ez and E, are independent events Calculate P(E, and E, and Ey) 44 a. P(E, and B) - (Round to four decimal places as needed.) b. P (E, or B)(Round to four decimal places as needed) c. P (E, and E, and E) - (Round to four decimal places as needed.)