Until recently, an average of 60 out of every 100 patients have survived a particularly severe infection. When a new dru

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Until Recently An Average Of 60 Out Of Every 100 Patients Have Survived A Particularly Severe Infection When A New Dru 1 (110.78 KiB) Viewed 88 times

Until recently, an average of 60 out of every 100 patients have survived a particularly severe infection. When a new drug was administered to a random sample of 15 patients with the infection, 12 survived. Does this prove evidence that the new drug is effective? Let X denote the number of patients who survive. Then X-B(15,p), and it is required to test Ho: p=0.6 (not effective) Hi:p> 0.6 (effective, one-tailed) Now assuming Ho is true. X-B(15,0.6), and so P( X = 12) = 0.62 0.41 = 0.06339 P(X = 13) = 1 0.69 0.4 =0.02194 P(x = 14) = 0.64 0.4' =0,00470 =(19)0.0 P(X=15) =(13)0.01 0.615 0.49 = 0.00047 Hence, under Ho, the probability of 1. 15 patients surviving = 2. 14 or 15 patients surviving 3. 13, 14, or 15 patients surviving 4. 12, 13, 14 or 15 patients surviving = NOTE: Since P(X> 12) = 0.09050 >0.05, then Ho cannot be rejected