Answer Happy

4-Two types of plastic are suitable for use by an electronic calculator manufacturer. The breaking strength of this plastic is important. It is known that the plastic breaking strength is normally distributed and 0, = 0, = 10 psi . From random samples of n1=10 and n2=12 we obtain y; = 164.5 and y, =155.0. The company will not adopt plastic 1 unless its breaking strength exceeds that of plastic 2 by at least 10psi? a. Set up the appropriate hypothesis on the mean u. b. Based on following Minitab output, should the manufacturer use plastic 17 Why? Use Q=0.05 Two-Sample T-Test and a Sample N Mean StDev SE Mean 1 10 164.50 1.00 0.32 2 12 155.00 1.00 0.29 Difference-mu(1)-mu(2) Estimate for difference: 9.500 T-test: T-value=-1.17 P-value=0.872 DF=20 Both use Pooled StDev=1.0000