I'm a little lost with this, any help would be great! Part 1 Part 2 Part 3
Posted: Fri Dec 24, 2021 10:16 am
I'm a little lost with this, any help would be great!
Part 1
Part 2
Part 3
You are conducting a study to see if the probability of catching the flu this year is significantly more than 0.22. Thus you are performing a right-tailed test. Your sample data produce the test statistic z = 2.013. Find the p-value accurate to 4 decimal places.
In a certain school district, it was observed that 29% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 155 out of 435 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the a = 0.02 level of significance. What is the hypothesized population proportion for this test? p= (Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.) Based on the statement of this problem, how many tails would this hypothesis test have? O one-tailed test O two-tailed test
Choose the correct pair of hypotheses for this situation: (A) (B) Ho: p = 0.29 Ho:p = 0.29 Ha:p < 0.29 H:P +0.29 = (C) Ho:p = 0.29 Ha:p > 0.29 (D) (E) (F) Ho:p = 0.356 Ho:p= 0.356 Ho:p = 0.356 Ha:p < 0.356 Ha:p + 0.356 Ha:p > 0.356 = = = (A) (B) (C) (D) (E) (F) Using the normal approximation for the binomial distribution (without the continuity correction), what is the test statistic for this sample based on the sample proportion? 2 = (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the P-value for this sample. P-value = (Report answer as a decimal accurate to 4 decimal places.) This P-value and test statistic) leads to a decision to... O reject the null O accept the null O fail to reject the null O reject the alternative
As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program. There is not sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program. The sample data support the assertion that there is a different proportion of only children in the G&T program. There is not sufficient sample evidence to support the assertion that there is a different proportion of only children in the G&T program.
You wish to test the following claim (Ha) at a significance level of a = 0.001. = Ho:u = 72.8 Ha:μ > 72.8 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 15 with mean M = 87.7 and a standard deviation of SD = 19.3. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null
As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 72.8. O There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 72.8. O The sample data support the claim that the population mean is greater than 72.8. There is not sufficient sample evidence to support the claim that the population mean is greater than 72.8.
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In a certain school district, it was observed that 29% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 155 out of 435 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the a = 0.02 level of significance. What is the hypothesized population proportion for this test? p= (Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.) Based on the statement of this problem, how many tails would this hypothesis test have? O one-tailed test O two-tailed test
Choose the correct pair of hypotheses for this situation: (A) (B) Ho: p = 0.29 Ho:p = 0.29 Ha:p < 0.29 H:P +0.29 = (C) Ho:p = 0.29 Ha:p > 0.29 (D) (E) (F) Ho:p = 0.356 Ho:p= 0.356 Ho:p = 0.356 Ha:p < 0.356 Ha:p + 0.356 Ha:p > 0.356 = = = (A) (B) (C) (D) (E) (F) Using the normal approximation for the binomial distribution (without the continuity correction), what is the test statistic for this sample based on the sample proportion? 2 = (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the P-value for this sample. P-value = (Report answer as a decimal accurate to 4 decimal places.) This P-value and test statistic) leads to a decision to... O reject the null O accept the null O fail to reject the null O reject the alternative
As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program. There is not sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program. The sample data support the assertion that there is a different proportion of only children in the G&T program. There is not sufficient sample evidence to support the assertion that there is a different proportion of only children in the G&T program.
You wish to test the following claim (Ha) at a significance level of a = 0.001. = Ho:u = 72.8 Ha:μ > 72.8 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 15 with mean M = 87.7 and a standard deviation of SD = 19.3. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null
As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 72.8. O There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 72.8. O The sample data support the claim that the population mean is greater than 72.8. There is not sufficient sample evidence to support the claim that the population mean is greater than 72.8.