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FB = 200N A 300 2 m FA = 100N OMA = 2FB N-m Counterclockwise OMA = 2Fgcos(30°) N-m Counterclockwise OMA = 2Fpsin(30°) OM

Posted: Sun Sep 05, 2021 5:12 pm
by answerhappygod
Fb 200n A 300 2 M Fa 100n Oma 2fb N M Counterclockwise Oma 2fgcos 30 N M Counterclockwise Oma 2fpsin 30 Om 1
Fb 200n A 300 2 M Fa 100n Oma 2fb N M Counterclockwise Oma 2fgcos 30 N M Counterclockwise Oma 2fpsin 30 Om 1 (85.73 KiB) Viewed 76 times
FB = 200N A 300 2 m FA = 100N OMA = 2FB N-m Counterclockwise OMA = 2Fgcos(30°) N-m Counterclockwise OMA = 2Fpsin(30°) OMA = 2(Fosin(30°) + Focos(30°)) N-m Counterclockwise N-m Counterclockwise