FB = 200N A 300 2 m FA = 100N OMA = 2FB N-m Counterclockwise OMA = 2Fgcos(30°) N-m Counterclockwise OMA = 2Fpsin(30°) OM
Posted: Sun Sep 05, 2021 5:12 pm
FB = 200N A 300 2 m FA = 100N OMA = 2FB N-m Counterclockwise OMA = 2Fgcos(30°) N-m Counterclockwise OMA = 2Fpsin(30°) OMA = 2(Fosin(30°) + Focos(30°)) N-m Counterclockwise N-m Counterclockwise