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A 215 g sample of CaCO3 is reacted with 201 g of H3PO4 according to the equation: 3CaCO3(s) + 2H3PO4(aq)- Ca3(PO4)2(s) +
Posted: Fri Jun 10, 2022 11:28 am
by correctanswer
- A 215 G Sample Of Caco3 Is Reacted With 201 G Of H3po4 According To The Equation 3caco3 S 2h3po4 Aq Ca3 Po4 2 S 1 (19.54 KiB) Viewed 52 times
A 215 g sample of CaCO3 is reacted with 201 g of H3PO4 according to the equation: 3CaCO3(s) + 2H3PO4(aq)- Ca3(PO4)2(s) + 3CO₂(g) + 3H₂O(l) Molar masses (g mol-¹): CaCO3 = 100.10, H3PO4= 98.03, Ca3(PO4)2 = 233, CO₂ = 44. H₂O = 18 The amount of Ca in the final product after the reaction reached completion is: