Answer Happy

Question 2 A game takes a ball through N complete revolutions of a radius R circular accelerator (constant angular acceleration) before launching it out onto a tilting table. Once it enters the table it undergoes acceleration perpendicular to its launch velocity of a(t) = AB² cos(Bt). The goal is to choose the angular acceleration so that when the ball reaches a wall a distance D from the launch point that it will exit through a small hole (that you must also place). To do so it must be travelling perpendicular to the wall the instant it encounters it. The person to get the ball through the hole fastest wins. What angular acceleration do you choose and where do you place the hole? Top View Start from rest N revolutions a(t) = AB² cos(Bt) → [0(0) = Exit hole location? Up +, Down - Must exit to wall. Want shortest time R α =?