Answer Happy

ements Recordings ents Services Counseling Eval cht OneDrive STEP 3 Capacitors are charged by current flowing in the circuit. So we can expect that changing the amount of current will affect how long the circuit takes to charge the capacitor. Since the current is affected by the total resistance in the circuit, the easiest way to adjust the current is to change the resistance. Remove the 100 resistor at R2 and replace it with a 2k resistor, as illustrated in the schematic below. What effect will this change have on the rate of capacitor charging? Why? • What effect will this change have on the rate of capacitor discharging? Why? R1 R2 2kQ 5.1 KQ wwww PSB + C1 B1 5 V 100 μF SW1 With C1 discharged and the 2k0 resistor connected at R2, test the circuit. Note: The capacitor will slowly discharge through B1, but it takes a fairly long time. Discharging the capacitor yourself between tests ensures that each circuit test is done under the same conditions. Replace the 2kQ resistor at R2 with a 5k10 resistor and test again. Replace the 5k102 resistor at R2 with a 10k0 resistor and test once more. . When you press and hold the button at SW1, is the number of beeps per minute increased, or decreased, by more resistance at R2? (Hint: If the number of beeps has not decreased, check your circuit and test your components because something is not right)
Question 3 6 When you increased the value of the resistor at R2 in Step 3, what effect did this have on the rate of capacitor discharging, and why? O The rate of capacitor discharging was unaffected. The capacitor is only discharged through the buzzer in this circuit, so resistors placed at other locations will not affect the flow of current during the discharge cycle. The rate of capacitor discharging was decreased. We can infer this decrease by observing that the light emitted by the LED at D1 is significantly reduced during capacitor discharging after the resistance at R2 is increased. Since the flow of current to both the capacitor and the buzzer is limited by the resistance at R2, we can expect that decreasing that current (by increasing the value of the resistor), will limit all other functions of those components. The rate of both charging and discharging the capacitor will be decreased by further limiting the flow of current. The rate of capacitor discharging was increased. Using the water analogy for current, we see that when a restriction nozzle is placed at the end of a hose (acting as a 'water resistor'), the speed and pressure of the water flow is significantly increased. Similarly, the rate and power of capacitor charge and discharge will be significantly increased by the additional resistance.
Question 5 6 pts What reasoning supports the correct answer in the previous question? (CAUTION: You may lose points if the reasoning and the answer you chose above are in disagreement.) O Changing the resistor values had no significant effect on the number of beeps per minute, so the rate of capacitor charging and discharging is not related to the beeps emitted by the buzzer. Adding resistance at R2 decreased the current available for charging the capacitor, so the rate of charging was decreased and charging the capacitor took more time. The length of time between the beeps got longer when that happened, so that time between beeps must be while the capacitor is charging. During capacitor discharging, current through all parts of the circuit is reversed. Since the buzzer is directional, it can only emit a beep during capacitor discharging because only then does the current move in the right direction to flow through the buzzer. When the capacitor is discharging, it temporarily interrupts the current from the PSB. This interruption is responsible for the silence in between beeps. When the current from the PSB resumes, the buzzer is able to make a sound again. Question 6 10 pts
ling D 6 pts Question 4 Does the buzzer in this circuit emit a beep while the capacitor is being charged, or while it is being discharged? (The next question asks about the reasoning that supports this answer.) While the capacitor is being charged. Both, at different times. While the capacitor is being discharged. ONeither.