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The equilibrium constant, Kc, for the following reaction is 1.80x10-2 at 698K. 2HI(g) =H₂(g) + 12(9) If an equilibrium m
Posted: Thu Jun 09, 2022 7:51 am
by answerhappygod
- The Equilibrium Constant Kc For The Following Reaction Is 1 80x10 2 At 698k 2hi G H G 12 9 If An Equilibrium M 1 (36.88 KiB) Viewed 45 times
The equilibrium constant, Kc, for the following reaction is 1.80x10-2 at 698K. 2HI(g) =H₂(g) + 12(9) If an equilibrium mixture of the three gases in 10.8 L container at 698K contains 0.398 mol of HI(g) and 0.361 mol of H₂, the equilibrium concentration of I2 is M. Submit Answer Retry Entire Group 9 more group attempts remaining