At a certain temperature, 0.330 mol CH₂ and 0.948 mol H₂S are placed in a 4.00 L container. CH₂(g) + 2 H₂S(g) = CS₂(g) +
Posted: Thu Jun 09, 2022 7:36 am
At a certain temperature, 0.330 mol CH₂ and 0.948 mol H₂S are placed in a 4.00 L container. CH₂(g) + 2 H₂S(g) = CS₂(g) + 4H₂(g) At equilibrium, 11.1 g CS, is present. Calculate K..