Answer Happy • For cyanide ion (CN¹-) the Kb = [OH¹-][HCN] / [CN¹-] [CN¹-] / [OH¹-][HCN] [OH-][HCN¹] / [CN] O [C4 ][N³+] / [CN¹-] none

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For cyanide ion (CN¹-) the Kb = [OH¹-][HCN] / [CN¹-] [CN¹-] / [OH¹-][HCN] [OH-][HCN¹] / [CN] O [C4 ][N³+] / [CN¹-] none

Posted: Thu Jun 09, 2022 7:22 am

by answerhappygod

: For Cyanide Ion Cn The Kb Oh Hcn Cn Cn Oh Hcn Oh Hcn Cn O C4 N Cn None 1 (48.27 KiB) Viewed 32 times

For cyanide ion (CN¹-) the Kb = [OH¹-][HCN] / [CN¹-] [CN¹-] / [OH¹-][HCN] [OH-][HCN¹] / [CN] O [C4 ][N³+] / [CN¹-] none of the above