You discover a bottle of compound A with the label “C8H14” in the lab. Compound A decolourizes Br2 in CCl4 and becomes c
Posted: Thu Jun 09, 2022 7:07 am
You discover a bottle of compound A with the label
“C8H14” in the lab. Compound A decolourizes Br2 in CCl4
and becomes compound B (C8H14Br2). Treatment of B with
two moles of potassium hydroxide produces compound C. Treatment of
C with acidic potassium permanganate produces two four- carbon
compounds: a diketone and a dialdehyde, respectively. However,
treatment of A with acidic potassium permanganate produces only one
product—compound D (shown below). Identify compounds A through C,
clearly showing how you reached your conclusions.
Can you please explain how you found identity of each compound
in detail?
“C8H14” in the lab. Compound A decolourizes Br2 in CCl4
and becomes compound B (C8H14Br2). Treatment of B with
two moles of potassium hydroxide produces compound C. Treatment of
C with acidic potassium permanganate produces two four- carbon
compounds: a diketone and a dialdehyde, respectively. However,
treatment of A with acidic potassium permanganate produces only one
product—compound D (shown below). Identify compounds A through C,
clearly showing how you reached your conclusions.
Can you please explain how you found identity of each compound
in detail?