The position of a particle traveling along a straight line is s(t) = (Cot³-C₁t²+C₂) ft, where t is in seconds and Co, C₁
Posted: Wed Jun 08, 2022 8:12 pm
The position of a particle traveling along a straight line is s(t) = (Cot³-C₁t²+C₂) ft, where t is in seconds and Co, C₁, C₂ are a constants. If s = 4 ft when t = 0 and s = 16 ft, when t = 4. What is the total distance traveled during the time interval t = 0 to t = 4 s?