Answer Happy

From the window of a building, a ball is tossed from a height yo above the ground with an initial velocity of 7.50 m/s and angle of 25.0° below the horizontal. It strikes the ground 4.00 s later. (a) If the base of the building is taken to be the origin of the coordinates, with upward the positive y-direction, what are the initial coordinates of the ball? (Use the following as necessary: Yo. Assume SI units. Do not substitute numerical values; use variables only.) x₁ = 0 Y;= hm X (b) With the positive x-direction chosen to be out the window, find the x- and y-components of the initial velocity. = 6.80 V₁ Vi, x² ✔ m/s × -3.70 Vi, y Your response differs from the correct answer by more than 10%. Double check your calculations. m/s (c) Find the equations for the x- and y-components of the position as functions of time. (Use the following as necessary: yo and t. Assume SI units.) x= 6.80t m y=y-3.70t - 281² m X (d) How far horizontally from the base of the building does the ball strike the ground? 27.2 m (e) Find the height from which the ball was thrown. 91.1 m (f) How long does it take the ball to reach a point 10.0 m below the level of launching? S