Answer Happy

please double check my work. Not sure if I'm following/doing this correctly. I'm assuming M is the initial mass of the puck, and m is hanging mass force.
1. Click on Begin 2 Then click on Masses 3. Set the mass of the Hover Puck, M, at 500 grams. Use this mass for all determinations.. Set the mass of the hanging mass. 4 5 When the mass of the Hover Puck and mass of the hanging mass has been set click Return 6. The force that is applied to the Hover Puck is from the hanging mass being acted on by gravity, so that E = mg/where m is the hanging mass in kg and g is the acceleration due to gravity, 9.8 m/s2. Remember that the mass must be in kg for this calculation. wis Calcula Five runs will be completed using the five hanging mass values in the Table. Applied F = M. g late the 8. 10. Calculate the Force applied (mg) and record it in column (2) of the data sheet. Record the time for the Hover Puck to travel 1.00 m in column (3) of the data sheet. Calculate the average velocity of the Hover Puck using Vave = 1.00 meter/t, and record it in column (4) of the data sheet. Calculate the final velocity of the Hover Puck using the relationship Vinal = 2 Vave and record it in Column (5) of the data sheet. 1. 12. 13. Calculate the acceleration of the Hover Puck by dividing the V, by the time and record it in column (6) of the data sheet. Calculate the acceleration of the Hover Puck + hanging mass using a = F/(M + m) and record it in column (7) of the data sheet. (This assumes a coefficient of friction = 0) DATA TABLE M + (m) = hang mess Mass of Hover Puck = M = 500 g = 0.500 kg Distance (s) = 1.00 meters (Read from the data sheet) (1) (2) (3) (5) (6) (7) Hanging Force Average Final a a Mass Hanging Time Velocity Hover Puck system Velocity Col (4) kg Mass seconds. 1.00 meter Col (5) Col (2) X 9,8 + Time X 2 + Time + (M+m) 9.8 X.01 3.273 .306x2 log 0.010 .612/3.273.698 .098 (.5+.01) = 192. 0612 0187 9.8 X.02 205 0.020 196 2,348 .852 .363 377 9.8 x.05 50g 0.050 .490 656 1.312 0860 0 100 S 9,8×0.1 (3d) 0.100 .१४० 0899 1.798 1.617 9.8×0,2 1.633 1.96/.5+,2 1.96 2.41 2.904 2.800 2009 0.200 1.525 1.112 0.830 \/(32 306 \/(36) e426 \(32) Xze) 1.205 F=(2) 1= F/(₁01 +15)) 24.5