An object is in static equilibrium when the vector sum of all the forces acting on that object is equal to zero. This is
Posted: Wed Jun 08, 2022 1:27 pm
Part 1 1. Hang 100g at both ends of the strings, as m, and m3 in Figure 1. Note that the mass hangers each have a mass of 50g. Now hang 90g at the center, m, in Figure 1. Measure the angle between string 1 and the loop attached to the center hanger, string 2. This angle is labeled 0, in Figure 1. 0₂² 117° 01, see Figure 2, is then equal to ₁ minus the 90° between the horizontal and the vertical. m3 m₁ 0₁ = 27° วา 100g 1009 Measure the angle b shown in Figure 1. Figure 2 = 4. 0₂ is then equal to 0, minus the 90° between the horizontal and the vertical. 0₂= 27° 5. T1, T2, and T3 are the tensions in each of the strings, are shown in Figure 3. In figure 3, a) Draw the x-y coordinate system; b) Label the components Tx and Ty for each T; c) Label 0₁ and 0₂. T₁ T3 T₂ Figure 3 6. Since the system is in equilibrium, the tensions are equal to the weights hanging on the 2. 3. m₂ 909
end of the strings. |I₁|=100g 11₂1= 90g |13|= 100g 7. Use the measured angles 0₁ and 0₂ to calculate the horizontal (x) and the vertical (y) components of T₁, T2, and T3. Tix = T2x = T3x = Tly = T2y = T3y = 8. Use the results in 7 to show that the equilibrium conditions of equation 2 are satisfied by your experimental values.