Answer Happy

NEED HELP WITH PART 2(the hanging mass in part 1 is 170.29g)-in part 2 the mass at 95cm is 199.74g-the 10cm mass is 440.08g-and then the clamps holding each mass are 21.75g
(the hanging mass in part 1 is 170.29g)
-in part 2 the mass at 95cm is 199.74g
-the 10cm mass is 440.08g
-and then the clamps holding each mass are 21.75g
PROCEDURE Part 1 1. Weigh the meter stick with the triple-beam balance. 2. Locate the center of mass of the meter stick by balancing with a small clamp. 3. Pivot meter stick about the 25cm mark. Add mass to the 10cm mark until the stick is balanced horizontally (see figure below). pivot point 10cm M 4. Draw a Free-Body Diagram for the meter stick. 5. Calculate the net torque (sum of the torques) about the 25 cm mark. Do not forget to include the mass of the small clamp used to attach the mass at the 10cm mark. 6. Calculate the tension in the string supporting the meter stick by using Σ F. Part 2 1. Pivot meter stick about the 40cm mark. Add 200g to the 95 cm. Add mass to the 10cm mark until the stick is balanced horizontally. 2. Draw a Free-Body Diagram for the meter stick. 3. Calculate the tension in the string supporting the meter stick by FIRST calculating the net torque (sum of the torques) about the 75 cm mark. Do not forget to include the mass of the small clamps used to attach the masses at the 95cm and 10cm marks. 4. Calculate the tension in the string supporting the meter stick by calculating ΣFy. 5. Compare results for the tension in the string. Take the result from (4) to be the expected value. 25cm