5. A capacitor of 1800 DF is fully charged using a D.C. voltage supply. It is then connected across a resistor of unknow
Posted: Wed Jun 08, 2022 10:49 am
- 5 A Capacitor Of 1800 Df Is Fully Charged Using A D C Voltage Supply It Is Then Connected Across A Resistor Of Unknow 1 (27.81 KiB) Viewed 27 times
- 5 A Capacitor Of 1800 Df Is Fully Charged Using A D C Voltage Supply It Is Then Connected Across A Resistor Of Unknow 2 (44.03 KiB) Viewed 27 times
- 5 A Capacitor Of 1800 Df Is Fully Charged Using A D C Voltage Supply It Is Then Connected Across A Resistor Of Unknow 3 (15.52 KiB) Viewed 27 times
- 5 A Capacitor Of 1800 Df Is Fully Charged Using A D C Voltage Supply It Is Then Connected Across A Resistor Of Unknow 4 (15.52 KiB) Viewed 27 times
- 5 A Capacitor Of 1800 Df Is Fully Charged Using A D C Voltage Supply It Is Then Connected Across A Resistor Of Unknow 5 (30.55 KiB) Viewed 27 times
- 5 A Capacitor Of 1800 Df Is Fully Charged Using A D C Voltage Supply It Is Then Connected Across A Resistor Of Unknow 6 (29.63 KiB) Viewed 27 times
(a) Show that the time constant of the circuit is about 0.8 s. Time constant 1/e* (Io) = 5.4 /e -5.4/2.71 = 1.98A 1 = t = RC = 0.8s (b) Hence, calculate the resistance of the circuit. RC=t R=0.8/ 1800 μ R 1103.63 ohm
5. A capacitor of 1800 DF is fully charged using a D.C. voltage supply. It is then connected across a resistor of unknown resistance and allowed to discharge. The current through the resistor is measured using an ammeter and a current-time graphs is plotted
anted Coated current/A V M 2 1 R C finding (1 mark) 0 0.5 1.0 1.5 20 3.0 time s I (a) Show that the time constant of the circuit is about 0.8 s. Time constant 1/e* (lo) <= 5.4/e -5.4/2.71 = 1.98A 1 = t = RC = 0.8s
(b) Hence, calculate the resistance of the circuit. RC t R=0.8/ 1800 μ R 1103.63 ohm