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The specific membrane current of the Hodgkin-Huxley model is given by: Im = Ī₁(V − E₁) + ÿên¹ (V − Ek) + Īnam³h(V − Ena)
Posted: Wed Jun 08, 2022 9:45 am
by answerhappygod
- The Specific Membrane Current Of The Hodgkin Huxley Model Is Given By Im I V E Yen V Ek Inam H V Ena 1 (75.72 KiB) Viewed 22 times
The specific membrane current of the Hodgkin-Huxley model is given by: Im = Ī₁(V − E₁) + ÿên¹ (V − Ek) + Īnam³h(V − Ena) - Given that the probability that a subunit of potassium channel is open n = 0.891- 0.376e and the maximal open conductance JK = 25.3 mS/cm². Find the potassium conductance gk at steady state.