Estimate the stoichiometric air to fuel ratio for a 100% ethanol (CH3CH2OH) fuel (mole/mole). One mole of CH3CH2OH = 46
Posted: Wed Jun 08, 2022 9:29 am
Estimate the stoichiometric air to fuel ratio for a 100% ethanol
(CH3CH2OH) fuel
(mole/mole).
One mole of CH3CH2OH = 46g; one mole of O2 = 32g; one mole of N2 =
28g.
Note: Air is 21% O2 by volume.
Assume the following reaction.
6 CH3CH2OH + 36 O2 + 135.36 N2 → 12 CO2 + 18 H2O + 135.35 N2
(CH3CH2OH) fuel
(mole/mole).
One mole of CH3CH2OH = 46g; one mole of O2 = 32g; one mole of N2 =
28g.
Note: Air is 21% O2 by volume.
Assume the following reaction.
6 CH3CH2OH + 36 O2 + 135.36 N2 → 12 CO2 + 18 H2O + 135.35 N2