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Compound X. CHCl, is a chiral product of the radical chlorination of 4-methylheptane. X reacts in Sy2 fashion with Nat i

Posted: Thu Dec 02, 2021 7:36 am
by answerhappygod
Compound X Chcl Is A Chiral Product Of The Radical Chlorination Of 4 Methylheptane X Reacts In Sy2 Fashion With Nat I 1
Compound X Chcl Is A Chiral Product Of The Radical Chlorination Of 4 Methylheptane X Reacts In Sy2 Fashion With Nat I 1 (23.88 KiB) Viewed 120 times
Compound X Chcl Is A Chiral Product Of The Radical Chlorination Of 4 Methylheptane X Reacts In Sy2 Fashion With Nat I 2
Compound X Chcl Is A Chiral Product Of The Radical Chlorination Of 4 Methylheptane X Reacts In Sy2 Fashion With Nat I 2 (27.33 KiB) Viewed 120 times
Compound X Chcl Is A Chiral Product Of The Radical Chlorination Of 4 Methylheptane X Reacts In Sy2 Fashion With Nat I 3
Compound X Chcl Is A Chiral Product Of The Radical Chlorination Of 4 Methylheptane X Reacts In Sy2 Fashion With Nat I 3 (27.18 KiB) Viewed 120 times
Compound X Chcl Is A Chiral Product Of The Radical Chlorination Of 4 Methylheptane X Reacts In Sy2 Fashion With Nat I 4
Compound X Chcl Is A Chiral Product Of The Radical Chlorination Of 4 Methylheptane X Reacts In Sy2 Fashion With Nat I 4 (21.48 KiB) Viewed 120 times
Compound X. CHCl, is a chiral product of the radical chlorination of 4-methylheptane. X reacts in Sy2 fashion with Nat in acetone to form Z, CH11. When the reactant is the R-enantiomer of X, only the R-enantiomer of Zis formed Draw a structural formula for Xdo not show stereochemistry . Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right comer. Separate structures with + signs from the drop-down menu.
Compounds X and Y are both C3HCl products formed in the radical chlorination of pentane. Base-promoted E2 elimination of X and Y gives, in each case, a single CH1o alkene (ignoring double bond stereochemistry) Both X and Y react in Sy2 fashion with sodium iodide in acetone; Y reacts faster than X What is the structure of Y? . Do not use stereobonds in your answer. . In cases where there is more than one possible structure for each molecule, just give one for each • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. .
Draw the major organic product(s) of the following reaction. CH3 H3C-C-CI H2O CH3 • You do not have to consider stereochemistry. • If no reaction occurs, draw the organic starting material. • When Syl & El pathways compete, show both the substitution and the elimination products. • Separate multiple products using the + sign from the drop-down menu. • Do not include counter-ions, e.g., Na', I, in your answer.
Draw the major organic product(s) of the following reaction. th Br HO excess NH3 • You do not have to consider stereochemistry. • If no reaction occurs, draw the organic starting material. • When Syl & El pathways compete, show both the substitution and the elimination products. • Separate multiple products using the + sign from the drop-down menu. . Do not include counter-ions, e.g., Na'. 1', in your answer