Answer Happy

Problem 1.3-4 A circular aluminum tube of length L=420 mm is loaded in compression by forces P (see figure). The hollow segment of length 1/3 has outside and inside diameters of 60 mm and 35 mm, respectively. The solid segment of length 21/3 has diameter of 60 mm. A strain gage is placed on the outside of the hollow segment of the bar to measure normal strains in the longitudinal direction. (a) If the measured strain in the hollow segment is e,- 470 x 10, what is the strain e, in the solid part? (Hint: The strain in the solid segment is equal to that in the hollow 13 segment multiplied by the ratio of the area of the hollow to that of the solid segment). Strain gage (b) What is the overall shortening & of the bar? (e) If the compressive stress in the bar cannot exceed 48 MPa. what is the maximum permissible value of load P? 420 mm- a) €₂= ? Es = &n x An An= I (d₂²-d₁²) A== Id₂ As 2 4 b) == § Ss = 21€ Eh= Eh 늘 ST c) 5 = P P = A6 A Ps= As 6s os = 6h= 48MPa → Sh= Ss + Sh Ph= Anon