Answer Happy

Consider an ionic crystal consisting of a pair of oppositely charged ions. The cation specie has a valence of +1, a radius of 0.09 nm, and an atomic mass of 40 g/mol. The anion specie has a valence of -1, a radius of 0.12 nm, and an atomic mass of 70 g/mol. The force of attraction in N (i.e., Newtons) between two oppositely charged ions is given by the following equation: (9 x 9 × 10+⁹ v-m/c) (e|z₁|)(e |²₂|) F = a In this equation: e = charge of an electron = 1.602 × 10-1⁹ C; Z1,2 = cation and anion valences; r = distance between ions; (V.C)_ 1 = 1 N m What is the coulombic force of attraction between the cation and the ion in units of N (i.e., Newtons)? Use scientific notation (e.g., 1.01e-02 N; e must be lowercase; must include units)