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Throughout this experiment the current is measured to be I = 1.533 mA. After being discharged capacitor 1 is charged thr

Posted: Tue Jun 07, 2022 12:42 pm
by answerhappygod
Throughout This Experiment The Current Is Measured To Be I 1 533 Ma After Being Discharged Capacitor 1 Is Charged Thr 1
Throughout This Experiment The Current Is Measured To Be I 1 533 Ma After Being Discharged Capacitor 1 Is Charged Thr 1 (135.39 KiB) Viewed 22 times
Throughout this experiment the current is measured to be I = 1.533 mA. After being discharged capacitor 1 is charged three times. The voltage versus time graphs are shown below. Use these to calculate the capacitance of capacitor 1. MEA MA Une for La Pad-b 0.0089 0.0100 Canon 1.000 Canon 1.000 Conations 1.000 RMGE0007985 V RSE: 0.008006 V -3.20 2143V 0.00630V Graph data Linear fit for Linear fit for Latest Potential Linear fit for Latest Potential Latest Potential Pot= mt + b Pot mt + b Pot mt + b m (Slope): 0.9089 V/s m (Slope): 0.9100 V/s m (Slope): 0.9100 V/s b (Y-intercept): -3.243 b (Y-intercept): -2.143 b (Y-intercept): -1.901 V Correlation: 1.000 RMSE: 0.007985 V V V Correlation: 1.000 RMSE: 0.008305 V Correlation: 1.000 RMSE: 0.008095 V C₁ = + 0.9100 V -1.901 V

After being discharged capacitor 2 is charged three times. The voltage versus time graphs are shown below. Use these to calculate the capacitance of capacitor 2. MŪRINXA/ wa OMBUSSPX// ^XPXA/ML#0 MEA MEA MA P PE-16 mp 1.976 V nap: 1.977 Condation 1.000 Canon 1.000 RSE: 0.007990 V RSE: 0.008108 V RSE: 0.007142 V Graph data: Linear fit for Latest Potential Linear fit for Latest Potential Linear fit for Latest Potential Pot mt + b Pot= mt + b Pot=mt + b m (Slope): 1.973 V/s m (Slope): 1.976 V/s m (Slope): 1.977 V/s b (Y-intercept): -3.684 V Correlation: 1.000 RMSE: 0.007986 V b (Y-intercept): -3.330 V Correlation: 1.000 RMSE: 0.008103 V b (Y-intercept): -3.051 V Correlation: 1.000 RMSE: 0.007582 V C₂ = ± μF 3.330 GADNY -3.061 V

After being discharged capacitor 3 is charged three times. The voltage versus time graphs are shown below. Use these to calculate the capacitance of capacitor 3. CAREX// wea +H@U^^{P%^/ XPXA/M ARIY SITY MA MA HEA Line for La Pa-1- 4278 ndipe 4.294a ba Canalution 1.000 0006470 V Contin 1.000 SE 0.01681V USE 0.007567V Graph data Linear fit for Latest Potential Linear fit for Latest Potential Linear fit for Latest Potential Pot= mt + b Pot= mt + b Pot= mt + b m (Slope): 4.278 V/s m (Slope): 4.295 V/s b (Y-intercept): -9.054 V Correlation: 1.000 RMSE: 0.01681 V m (Slope): 4.294 V/s b (Y-intercept): -6.868 V Correlation: 1.000 RMSE: 0.005470 V b (Y-intercept): -8.772 V Correlation: 1.000 RMSE: 0.007557 V C3 = ± μF 4064 4772V

A parallel circuit Use the values you calculated above to predict the capacitance of C2 and C3 connected in parallel with an uncertainty. C2,3 = ± μF C₂ and C3 are now connected in parallel and the voltage versus time graph recorded three times as they charge. The graphs are presented below. Use these to calculate the experimental value for C2,3, the capacitance of C₂ and C3 in parallel. *#^^/PX// MX1/M ₁^X^/HLO PR-1 Pab Candation 1.000 Condo 1.000 0.006630V 0.007736V SE 0.007 Graph data Linear fit for Latest Potential Linear fit for Latest Potential Linear fit for Latest Potential Pot=mt + b Pot=mt + b Pot=mt + b m (Slope): 1.345 V/s m (Slope): 1.344 V/s b (Y-intercept): -3.754 V Correlation: 1.000 RMSE: 0.007736 V m (Slope): 1.343 V/s b (Y-intercept): -4.816 V Correlation: 1.000 RMSE: 0.007888 V b (Y-intercept): -4.386 V Correlation: 1.000 RMSE: 0.006530 V C2,3 = ± μF Note: You will be asked to compare your prediction and measurement in the next question. You may want to jump to that now and then come back here. 4816V 4.300V

A series circuit Use the values you found above to predict the capacitance of C₁ and C₂ connected in series with an uncertainty. C1,2 = ± μF C₁ and C₂ are now connected in series and the voltage versus time graph recorded three times as they charge. The graphs are presented below. Use these to calculate the experimental value for C1,2, the capacitance of C₁ and C₂ in series. #XA/L IX//400 ^^/PX//WE AND V 2.901 493 Condations 1.000 Canon 1000 RUSE 0008032V Com 1.000 ME: 0.000697V RUS:0007516V Graph data Linear fit for Latest Potential Linear fit for Latest Potential Linear fit for Latest Potential Pot= mt + b Pot=mt + b Pot=mt + b m (Slope): 2.901 V/s m (Slope): 2.907 V/s b (Y-intercept): -5.025 V Correlation: 1.000 RMSE: 0.009597 V m (Slope): 2.906 V/s b (Y-intercept): -4.939 V Correlation: 1.000 RMSE: 0.008032 V b (Y-intercept): -4.471 V Correlation: 1.000 RMSE: 0.007516 V C = ± uF Note: You will be asked to compare your prediction and measurement in the next question. You may want to jump to that now and then come back here. 600V 447