Answer Happy

For the 3-phase, 3 wire system below. Compute for the line currents, total real power, total reactive power, total apparent power, and power factor of the load if V 20020 V, Vi= 2002240° V, V 2002-240° V 120 160 30 2002 40 Figure 1. Question number 2. You can use the sample problem below as guide answering the problem, please use 3 decimal points for the final answer! Sample Problem solution for guide (the given from this problem is different from the problem above) Z₁ =1222-/1622=2022-53.13°, Z₂ = 3+j4N2=592 253.13⁰ Z₂-2012 20⁰ EAB= 200 V20°, Esc-200 V Z-120°, Ec=200 V <120° Z₁ = Z₁ Z₂ +Z₁Z₁ + Z₂Zs = (20 22-53.13°) (5 52 253.13°) + (20 2 2-53.13°) (20 2200) +(52 253.13°) (20 5220°) = 100 £2 20° +400 2 Z-53.13° +100 52 253.13⁰ = 100 2+(240 2-/320 2) + (60 2+j80 (2) = 400 Ω - j240 Ω = 466.48 2 Z-30.96° L EZ, - EcZ₂ (200 V Z0°)(205220°) – (200 V Z120°)(52 253.13°) ZA Z₂ 4000 A 20°-1000 A 2173.13° 10.71 A 229.59⁰ 466.482-30.96 EncZ₂-EAZY (200 VZ-120°)(202Z-53.13°) - (200 V Z0°)(2012 20°) Zo ZA 4000 A 2-173.13°-4000 A 20° -17.12 A Z-145.61° 466.482-30.96º Ecizy-Ecz (200 V <120°)(5 £253.13°) - (200 VZ-120°)(20£2-53.130) Z₂ ZA 1000 A 2173.13°-4000 A Z-173.13° -=6.51 A 242.32° 466.482-30.96 Pr=11202 +1242 +12052 =1376.45 W +1172.38 W +847.60 W = 3396.43 W Qr=1162+1 32-1835.27 VAR(C)+879.28 VAR(L) = 955.99 VAR(C) S₁-√√P+Q-3508.40 VA PL- 3396.43 W F,- = 0.968 (leading) ST 3508.40 VA