A sinusoidal voltage source of v(t)=240√2 sin(2*pi*60t) V is applied to a nonlinear load, resulting in current i(t)= 8 s
Posted: Tue Jun 07, 2022 12:30 pm
A sinusoidal voltage source of v(t)=240√2
sin(2*pi*60t) V
is applied to a nonlinear load, resulting in current i(t)= 8
sin(2*pi*60 t) + 4 sin (4*pi*60t) A.
Determine (a) the power absorbed by the load. (b) the power
factor of the load. (c) the distortion factor and (d) the total
harmonic distortion of the load current.
Q1. VRUS= = 240 IRUS TE A sinusoidal voltage source of (t) = 240V2 sin (2760) V is applied to a nonlinear load, resulting in a current i(t) = 8 sin(2607) + 4 sin (4760) A. Determine (a) the power absorbed by the load, (b) the power factor of the load. (c) the distortion factor, and (d) the total harmonic distortion of the load current. (CLO's #1)
sin(2*pi*60t) V
is applied to a nonlinear load, resulting in current i(t)= 8
sin(2*pi*60 t) + 4 sin (4*pi*60t) A.
Determine (a) the power absorbed by the load. (b) the power
factor of the load. (c) the distortion factor and (d) the total
harmonic distortion of the load current.
- A Sinusoidal Voltage Source Of V T 240 2 Sin 2 Pi 60t V Is Applied To A Nonlinear Load Resulting In Current I T 8 S 1 (16.66 KiB) Viewed 39 times