Answer Happy

Posted: **Tue Jun 07, 2022 11:08 am**

: Given Amin 2db Converting In Normal Gain 2db 20 Log An 10 Amin 1 258 We Know Amin E Amin 1 E Gi 1 (58.88 KiB) Viewed 39 times

: Given Amin 2db Converting In Normal Gain 2db 20 Log An 10 Amin 1 258 We Know Amin E Amin 1 E Gi 2 (54.23 KiB) Viewed 39 times

: Given Amin 2db Converting In Normal Gain 2db 20 Log An 10 Amin 1 258 We Know Amin E Amin 1 E Gi 3 (60.44 KiB) Viewed 39 times

: Given Amin 2db Converting In Normal Gain 2db 20 Log An 10 Amin 1 258 We Know Amin E Amin 1 E Gi 4 (23.61 KiB) Viewed 39 times

Given, Amin = 2dB Converting in normal gain = 2dB = 20 Log An 10 Amin = 1.258 we know. Amin =√√√²+² E = √Amin - 1 E = Given. Amax. 30dB 30dB = 20 lag Amax Amax= 31.622 for Butterworth filter H(jw) = Ho 2n JITELES given √(1-258)²-1 Fs = 8 KH₂, <= 0.763 Fp = 2KH₂

ever Hыш) 1.258 31.622 (0.039је 0541 (1325 we know сове гор М = (0.039)2 (4) = 1209.726 Apply log on both side. мод n = 2.500 | nă 3 -ОКН =' Н. J1+1C0+763)2 (en 1 П 1+ (0.763) ² (2) ² 1 1+0.541 * (4)² 1-1 22

Wo = 13745, 107 aad /sec Jet R=8 KR. 31 - wo RC CHL Ro C 8x10x13745-107 c = 9.09 hf Ska www Vin A = 9.09 nf C=9.09nf 4- RE Redkn FC=9-09 nf R=8k TC=9.09 hf Vout

1. Design a Butterworth lowpass filter which has no more than 2 dB of loss for frequencies below 2 kHz and at least 30 dB of attenuation for frequencies above 8 kHz. Your final result should be a circuit with reasonable component values. 2. Use LTSpice to simulate the frequency response of your circuit from problem 1) above. Verify that it has all the Butterworth characteristics (0 dB DC gain, monotonic response, 3-dB frequency is correct). Place cursors on the gain plot at the corner frequencies to verify that it meets the specifications given. 3. Repeat problems 1) and 2) above for a filter with no more than 1.5 dB of loss below 2 kHz and at least 30 dB of attenuation above 5 kHz..