Answer Happy

If a solution containing 85.99 g of mercury(II) acetate is
allowed to react completely with a solution containing 12.026 g of
sodium sulfide, how many grams of solid precipitate will be formed?
mass: g How many grams of the reactant in excess will remain after
the reaction? mass: g Assuming complete precipitation, how many
moles of each ion remain in solution? If an ion is no longer in
solution, enter a zero (0) for the number of moles. Hg2+ : mol
C2H3O–2 : mol Na+ : mol S2− : mol
If a solution containing 85.99 g of mercury(II) acetate is allowed to react completely with a solution containing 12.026 g of g sodium sulfide, how many grams of solid precipitate will be formed? mass: g 09 How many grams of the reactant in excess will remain after the reaction? mass: 09 Assuming complete precipitation, how many moles of each ion remain in solution? If an ion is no longer in solution, enter a zero (0) for the number of moles. Hg2+: mol

Assuming complete precipitation, how many moles of each ion remain in solution? If an ion is no longer in solution, enter a zero (0) for the number of moles. Hg2+: mol C,H,02: mol Na+ : mol S2-: mol