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14. y'= -2t (1+ y²)/y, y(0) = 1 15. y'= (sin x)/y, y(π/2) = 1 16. y'= ex+y, y(0) = 0 17. y' = (1 + y²), y(0) = 1 18. y'=

Posted: Tue Jun 07, 2022 8:09 am
by answerhappygod
 1
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14. y'= -2t (1+ y²)/y, y(0) = 1 15. y'= (sin x)/y, y(π/2) = 1 16. y'= ex+y, y(0) = 0 17. y' = (1 + y²), y(0) = 1 18. y'= x/(1+2y), y(-1) = 0