(1 point) Find an equation of the tangent plane to the parametric surface x=3u+3v,y=3u2,z=2u−3vx=3u+3v,y=3u2,z=2u−3v at
Posted: Tue Jun 07, 2022 8:05 am
(1 point) Find an equation of the tangent plane to the
parametric surface
x=3u+3v,y=3u2,z=2u−3vx=3u+3v,y=3u2,z=2u−3v
at the point (15,12,−5)(15,12,−5).
Help Entering Answers (1 point) Find an equation of the tangent plane to the parametric surface x = 3u + 3v, y = 3u², 22u3v at the point (15, 12, –5). 2 = -x+y/3+6 Σ If you don't get this in 3 tries, you can see a similar example (online). However, try to use this as a last resort or after you have already solved the problem. There are no See Similar Examples on the Exams! Help Entering Answers Preview My Answers Submit Answers Show me another Results for this submission Entered Answer Preview -x+(y/3)+6 Y −x + +6 3
parametric surface
x=3u+3v,y=3u2,z=2u−3vx=3u+3v,y=3u2,z=2u−3v
at the point (15,12,−5)(15,12,−5).
- 1 Point Find An Equation Of The Tangent Plane To The Parametric Surface X 3u 3v Y 3u2 Z 2u 3vx 3u 3v Y 3u2 Z 2u 3v At 1 (34.51 KiB) Viewed 59 times