and absolute convergenc Σ a. (-1)" √√2n²-n b n=1
Posted: Tue Jun 07, 2022 6:44 am
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and absolute convergenc Σ a. (-1)" √√2n²-n b n=1
we need to tell whether it converge or diverge and if it is converget we need to tell it is conditionally or aboslutely convergent
and absolute convergenc Σ a. (-1)" √√2n²-n b n=1