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A 108-mH inductor is connected in parallel with a 2-k2 resistor. The current through the inductor is (t) = 35e-400 mA. F

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A 108-mH inductor is connected in parallel with a 2-k2 resistor. The current through the inductor is (t) = 35e-400 mA. F

Posted: Mon Jun 06, 2022 6:54 pm
by answerhappygod
A 108 Mh Inductor Is Connected In Parallel With A 2 K2 Resistor The Current Through The Inductor Is T 35e 400 Ma F 1
A 108 Mh Inductor Is Connected In Parallel With A 2 K2 Resistor The Current Through The Inductor Is T 35e 400 Ma F 1 (27.83 KiB) Viewed 29 times
A 108-mH inductor is connected in parallel with a 2-k2 resistor. The current through the inductor is (t) = 35e-400 mA. Find the voltage vg(1) across the resistor. The voltage vg() across the resistor is e-400tv.
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