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The combustion of 1.714 g1.714 g of propanol (C3H7OH)(C3H7OH) increases the temperature of a bomb calorimeter from 298.0

Posted: Thu Dec 02, 2021 5:56 am
by answerhappygod
The combustion of 1.714 g1.714 g of
propanol (C3H7OH)(C3H7OH) increases the temperature of a
bomb calorimeter
from 298.00 K298.00 K to 302.13 K.302.13 K. The
heat capacity of the bomb calorimeter
is 13.93 kJ/K13.93 kJ/K.
Determine Δ𝐻ΔH for the combustion of propanol to carbon
dioxide gas and liquid water.