Na B.0,- 10 H2O + 2 HCl → 4 H3B03 + 2 NaCl + 5 H,0 5
Posted: Thu Dec 02, 2021 5:32 am
- Na B 0 10 H2o 2 Hcl 4 H3b03 2 Nacl 5 H 0 5 1 (2.22 KiB) Viewed 74 times
A. % Composition by mass of each compound in the balanced chemical
equation
B. Mass to mass stoichiometry calculation
C. Limiting reagent
D. Excess Reagent
E. Amount (g) in excess
F. Percent Yield
G. Number of dosage form and packaging that can be produced from
stoichiometric calculation
Na B.0,- 10 H2O + 2 HCl → 4 H3B03 + 2 NaCl + 5 H,0 5