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Na B.0,- 10 H2O + 2 HCl → 4 H3B03 + 2 NaCl + 5 H,0 5

Posted: Thu Dec 02, 2021 5:32 am
by answerhappygod
Na B 0 10 H2o 2 Hcl 4 H3b03 2 Nacl 5 H 0 5 1
Na B 0 10 H2o 2 Hcl 4 H3b03 2 Nacl 5 H 0 5 1 (2.22 KiB) Viewed 75 times
Solve for the following:
A. % Composition by mass of each compound in the balanced chemical
equation
B. Mass to mass stoichiometry calculation
C. Limiting reagent
D. Excess Reagent
E. Amount (g) in excess
F. Percent Yield
G. Number of dosage form and packaging that can be produced from
stoichiometric calculation
Na B.0,- 10 H2O + 2 HCl → 4 H3B03 + 2 NaCl + 5 H,0 5