For a function y(x) we have that the derivative is: y'(x)=8x^6+6x+5 and that y(5)=1. The value of y(1) is:
Posted: Thu Jun 02, 2022 12:11 pm
For a function y(x) we have that the derivative is:
y'(x)=8x^6+6x+5 and that y(5)=1. The value of y(1) is:
y'(x)=8x^6+6x+5 and that y(5)=1. The value of y(1) is: