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One way to synthesize ethylamine (CH3CH₂NH₂) is from the reaction of ammonia (NH3) with chloroethane (CH₂CH₂C1). (1) NH3 + CH3CH₂Cl → CH₂CH₂NH₂ + HCI One problem with this synthesis route is that the reaction is not very selective, and ammonia may react with two chloroethane molecules to form diethylamine ((CH3CH₂)₂NH). (2) NH3 + 2CH₂CH₂Cl → (CH₂CH₂)₂NH + 2 HCI A mixture of x₁ = 0.470 mol NH3/mol, x₂ = 0.470 mol CH₂CH₂Cl/mol, and the remainder inerts is fed into a reactor. Within the reactor, the fractional conversion of CH3CH₂Cl is 0.780 and the fractional yield of CH3CH₂NH₂ is 0.580. [Fractional yield is the (moles of desired product formed)/(moles of product possible for complete conversion of the feed to the desired product).] Assume a 100 mol basis for the feed stream, and calculate the number of moles of each component entering the reactor and leaving in the product stream. Here is the process flow diagram for reference. 100 mol Reactor x, mol NH, /mol x₂ mol CH₂CH₂Cl/mol x₂ mol inerts/mol nmol NH3 n, mol CH₂CH₂CI nmol inerts n, mol CH,CH,NH, ng mol (CH,CH,),NH n, mol HCI How many moles of NH3 enter the reactor? mol NH3 How many moles of CH3CH₂Cl enter the reactor? mol CH3CH₂C1 How many moles of inerts enter the reactor? mol inerts How many moles of inerts leave the reactor? mol inerts n₂ = n3 = n6 || 47 47 6
How many moles of CH₂CH₂Cl leave the reactor? How many moles of CH₂CH₂NH₂ leave the reactor? How many moles of (CH₂CH₂)₂NH leave the reactor? How many moles of NH3 leave the reactor? How many moles of HCI leave the reactor? ng = n7 ng || n₁ = ng = Incorrect Incorrect Incorrect Incorrect Incorrect mol CH3CH₂C1 mol CH3CH₂NH₂ mol (CH3CH₂)2NH mol NH3 mol HCI