Answer Happy

The following data apply to a closed link traverse ABCDE.
The bearing to Station A from an Object X is 330° 40' 42”. The
bearing to Station E from an Object Y is 258° 05' 38”.
The coordinates of Station A = 5435.380mE, 957.460mN Station E =
4539.770mE, 880.286mN
Calculate the corrected coordinates at Stations B, C and D
adjusting any misclosures using Bowditch method.

In doing your calculations, follow the following steps and show
them clearly. (show at least one set of calculations for each
step)
(i) Calculate the bearings of each leg, using;
Bearing of a line (or Leg) =
SUM of Bearing of the Previous line + included angle at the given
station
+ 180° if SUM < 180°
- 180° if SUM is between 180° & 540°
- 540° if SUM > 540° (6 marks)
(ii) To find any angular misclosure, Compare the
calculated WCB and the given WCB for last Station E.
(2 marks)
(iii) If there is any misclosure, distribute
it equally among the stations and calculate the corrected
horizontal angles. (4 marks)
(iv) using these corrected horizontal angles,
recalculated the corrected bearing (corrected WCB) for each
leg. (6 marks)
(v) Using these bearings then calculate the
changes in Easting and Northing for each line using,
  L sin WCB   L cos WCB
(6 marks)
(vi) Get the algebraic sum of    to find the
Easting error eE and the Northing error eN.
Using them calculate the linear misclosure e =  (eE2 +
eN2). (2 marks)
(vii) To distribute the error using Bowditch
method,
Calculate Correction to Eastings, E, (for a given leg XY)
using
EXY = [ eE / D ] x Dxy Applied with the
opposite sign to e
E
Calculate Correction to Eastings, , (for a given leg XY)
using
NXY = [ e / SD ] x DXY
N

Applied with the opposite sign to e
N
D = sum of lengths of all legs
DXY = Length of the given leg XY (6
marks)
(viii) Using these corrections, re-calculate
the corrected    (2 marks)
(ix) Using the corrected   , and starting
from the first station (whose coordinates are already known),
calculate the coordinates (Eastings and Northings) of each
successive station. (6 marks)
Please answer Neatly on a paper