Answer Happy

Hello, it's control engineering and I have a problem with
getting angles of departures. In my calculation, the angle of
departure is around 30 degree. But when I use Matlab, the graph
doesn't seem to be the same (angle around 150 degree). Could you
answer two questions I have and get the angle of departure? Two
questions written in screen capture (blue ones on right)
I'm a beginner in this subject. Please help me kindly
4:30 PM Wed Jun 1 <88QQ Final 8 of 8 2 $ Grc= IP k(+3) 5²42545 K= k(s+3) GsH(s) = +25450 25+1) 1+G(s)H(s) = 0 s+²+155+25 +5k (s+3) = 0 poles -5 -1+2i, -1-2é -3 дело Asymbole (-5-(+26-1-21)-(-3) = 3-1 = 2+1 X180 3-1 q=0.1 = 90° - 270° Routh criterion S+7+(15+)5+25+15k=0 Break away point S²+75² +155+25 5 k(s+3) at S=2.9 d=0 Final lecture_note5 lecture note6 ☆ have a difficulty with getting departure angle (5²+25+5)(5+5) H(s) = 0.25+1 S²+25² +55+ 55² + los +25 S²+² +155+25 ... 2: my calculation • mallal Jet Je =-2 S² 52 s' So 1 7 9 b Asymtote 1575/c I 25+15k Re a= - (25+15k-7015+5k) = -201-801 31. •1 (20k+80) >o 6= - = (-a(25 tist= ) ) = 25+151 >0 stable at all K. 5 sum of angles 180? Is (from gene, not pols) included? Departure angle 0₁ +0₁+0₂ +0=180" 0₁ +90 +45 +atan &=180° 0₁ = 180-90-45°-14.04 = 30.96° 25+/5k 105 -35/5 k> - lecture_note7 k>-4 1.49% + ...