Braking Performance From a tractor-semitrailer combination, the tractor weighs 66.72kN and the semitrailer weighs 266.88
Posted: Thu Jun 02, 2022 9:59 am
Braking Performance
From a tractor-semitrailer combination, the tractor weighs
66.72kN and the semitrailer weighs 266.88kN. The wheelbase of the
tractor is 381cm, and the trailer axle is 1016cm behind the rear
axle of the tractor. The hitch point is 25cm in front of the
tractor rear axle and 122cm above the ground level. The center of
gravity of the tractor is 203.2cm behind the tractor front axle and
96.5cm above the ground. The center of gravity of the semitrailer
is 508cm in front of the trailer axle and 177.8cm above the ground.
What is the ideal braking effort distribution between the axles
that ensures all the tires being locked up at the same time on a
surface with the coefficient of road adhesion μ=0.6? Also
calculate the normal loads on the axles and the forces acting at
the hitch point.
Wf =
Wr =
Ws =
|C₁=Cr= Cse= ==μl Optimum braking condition: (maximum braking forces of all axles at the same time)
Cf= Fof Wf For Cr=wr, Cse= Wr , Fbs Ws
1. For the tractor =Wp +Wr= W₁+ WH Fbr vertical Whi Fof = CAWA +CrW₂ = @ W₁ +Fai Horizontal planta Wihi + Frih 3 + Wi (L₁-1₁ ~d, ) + Wrd, = Wech-di) → Moment about A 2. For the semi-trailer :r, -421 Whi+Ws = W₂ Fus Vertical 428 Fuit Geważ gwa Horizontal mount W2d2 +Frih3 =W2h2 +Ws/2 ⇒ moment about A
3. For the tractor-semitrailer combination Wf+W₂ +Ws = W₁ +W₂ CpWf+CrWr+Cse Ws = q (W₁+W₂) = Fox+For+Fbs w₁ h₁ + GW₂h₂+ Wr4 + Ws (Li-d₁ +2₂) = Will + W2(Li-d; + d2) → moments about B
Ra17 ha1 Wa Ra2 B Fbf 4₁ W₁ Wal d₂ ha2 W₂₁ Fi 0 + ch A Fbr Wr h₂ را + Ws Fbs
From a tractor-semitrailer combination, the tractor weighs
66.72kN and the semitrailer weighs 266.88kN. The wheelbase of the
tractor is 381cm, and the trailer axle is 1016cm behind the rear
axle of the tractor. The hitch point is 25cm in front of the
tractor rear axle and 122cm above the ground level. The center of
gravity of the tractor is 203.2cm behind the tractor front axle and
96.5cm above the ground. The center of gravity of the semitrailer
is 508cm in front of the trailer axle and 177.8cm above the ground.
What is the ideal braking effort distribution between the axles
that ensures all the tires being locked up at the same time on a
surface with the coefficient of road adhesion μ=0.6? Also
calculate the normal loads on the axles and the forces acting at
the hitch point.
Wf =
Wr =
Ws =
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Cf= Fof Wf For Cr=wr, Cse= Wr , Fbs Ws
1. For the tractor =Wp +Wr= W₁+ WH Fbr vertical Whi Fof = CAWA +CrW₂ = @ W₁ +Fai Horizontal planta Wihi + Frih 3 + Wi (L₁-1₁ ~d, ) + Wrd, = Wech-di) → Moment about A 2. For the semi-trailer :r, -421 Whi+Ws = W₂ Fus Vertical 428 Fuit Geważ gwa Horizontal mount W2d2 +Frih3 =W2h2 +Ws/2 ⇒ moment about A
3. For the tractor-semitrailer combination Wf+W₂ +Ws = W₁ +W₂ CpWf+CrWr+Cse Ws = q (W₁+W₂) = Fox+For+Fbs w₁ h₁ + GW₂h₂+ Wr4 + Ws (Li-d₁ +2₂) = Will + W2(Li-d; + d2) → moments about B
Ra17 ha1 Wa Ra2 B Fbf 4₁ W₁ Wal d₂ ha2 W₂₁ Fi 0 + ch A Fbr Wr h₂ را + Ws Fbs