Inverse z transform question when x[n] = cos(pi*n/2)+cos(pi*n/4) I've determined X(z) as the z transform of cos for the
Posted: Thu Jun 02, 2022 9:38 am
Inverse z transform question
when x[n] = cos(pi*n/2)+cos(pi*n/4)
I've determined X(z) as the z transform of cos for the above,
and Y(z) = X(z)(1-z^(-4))
but I don't know how to go back to the discrete time domain from
the above?
x[n] 2₁¹ 2¹ 2¹ 20 Z-1 Z-1 Z-1 Z-1 + y[n]
when x[n] = cos(pi*n/2)+cos(pi*n/4)
I've determined X(z) as the z transform of cos for the above,
and Y(z) = X(z)(1-z^(-4))
but I don't know how to go back to the discrete time domain from
the above?
x[n] 2₁¹ 2¹ 2¹ 20 Z-1 Z-1 Z-1 Z-1 + y[n]