Volume / mL TIME TEMPERATURE ос Mixture 4.0 M acetone 1.0 M HCI Ist run/min Time/s 0.0050 MI H2O 4.43 283 1 10 10 10 20
Posted: Thu Dec 02, 2021 5:22 am
- 1 (21.61 KiB) Viewed 96 times
- 2 (27.06 KiB) Viewed 96 times
- 3 (18.53 KiB) Viewed 96 times
- 4 (15.15 KiB) Viewed 96 times
- 5 (19.38 KiB) Viewed 96 times
- 6 (22.81 KiB) Viewed 96 times
- 7 (13.19 KiB) Viewed 96 times
- 8 (27.04 KiB) Viewed 96 times
MIXTURE (acetone) Time /s [HCI) M. V=M, V2 [12). M,V=M,V2 Rate [12] t mol/L.S M. V=M,V2 1 283 4X10=M,x 50 M2=0.80M 1 X 10 =M,X50 0.0050 X 1=M,X50 M2=0.20M M =0.0010M 0.0010 283 = 3.5 X10 2 3 4
1 2 Calculation of reaction order: Rate =[acetone)"[H+]"[12] =K[ ] [ ][ ]P =K[C]" ]P =K[ ] [ ][ ]' =K[]"[][]P 1. With respect to acetone: eq2/eql 3 - In-m in m=
Similarly calculate order with respect to H+ ,12 W.r.t H eq3/eq1 1 3 W.r.t 1, e94/eq1 4 Then calculate over all order-m+n+ P
Calculation of Rate constant (show the calculation in the report] Rate =K [acetone ]”[H+]"[12]. m= n= p- K- Rate (acetone)"[+]" N 3 4 Mixture KIL/M.] Average k at room teperature (20°C)
Calculation of Ea [BY USING MIXTURE 2] Temperature K Average time/s K In K 1/T Rate [Mol/L.s) 0°C +273=273 K 2220 Room Tem(mixture2) 20°C +273 = Kaverage 111 35°C+273 =
Plot graph between In K vs 1/T Slope- -Ea--slope XR- X 8.314) - _J/mol. KJ/mol
MIXTURE (acetone) Time /s [HCI) M. V=M_V3 [12]. M,V=M,V2 Rate [12] t mol/L.S M.V.=M, V2 1 283 4X10=M,x 50 M2=0.80M 1 X 10 =M2X50 0.0050 X 1=MX50 M2=0.20M M2=0.0010M 0.0010 283 = 3.5 X106 2 3 4 4