2/ (v²v-v²v) + g (22 − 2₁) + +F+Ws = 0 2α 2av lav. Ws = -nWp Power for Pumping in Flow System. Water is being pumped fro

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2/ (v²v-v²v) + g (22 − 2₁) + +F+Ws = 0 2α 2av lav. Ws = -nWp Power for Pumping in Flow System. Water is being pumped from an open water reservoir at the rate of 2.0 kg/s at 10°C to an open storage tank 1500 m away. The pipe used is schedule 40 3½-in. pipe and the frictional losses in the system are 625 J/kg. The surface of the water reservoir is 20 m above the level of the storage tank. The pump has an efficiency of 75%. (a) What is the kW power required for the pump? (b) If the pump is not present in the system, will there be a flow? Ans. (a) 1.143 kW P2-P1 P