-qh2o reaction -h for the reaction -h per mole
Posted: Thu Dec 02, 2021 5:17 am
-qh2o reaction
-h for the reaction
-h per mole
Heat of Neutralization 22.0c Original temp of HCl solution Original temp of NaOH solution 22.60 Final temp of neutralized mixture 35.30 Change in temp (use average original temp of 26.6C HCl and NaOH) QH20 for the reaction (get mass using 50.0 U ml solution and d=1.02 g/mL) AH for the reaction (egn 4) J AH per mole kJ/mol
Preaction = AH reaction = -9H20 (eqn 4) NaOH(s) - Na*(aq) + OH(aq); AH = AH solution (eqn 5) Solution with o int H'(am + OH(aq) - HO (O); AH = Anetration (en 6)
-27X-Blackboard-Expiration=1638176400000&X-Blackboard-Signature=WZUHUMegvo%2B0F 100% orua Suosiance q = Csxm X At (en 1) 4720 = -metal (eqn 2) now express heat flow in terms of Equation 1 for both the water and the metal, we get (Equation 3): q=CH20 X M20 X Atuzo = - metal X metal * Atmetar (eqn 3) 39F
-h for the reaction
-h per mole
- Qh2o Reaction H For The Reaction H Per Mole 1 (46.61 KiB) Viewed 56 times
- Qh2o Reaction H For The Reaction H Per Mole 2 (22.93 KiB) Viewed 56 times
- Qh2o Reaction H For The Reaction H Per Mole 3 (32.82 KiB) Viewed 56 times
Preaction = AH reaction = -9H20 (eqn 4) NaOH(s) - Na*(aq) + OH(aq); AH = AH solution (eqn 5) Solution with o int H'(am + OH(aq) - HO (O); AH = Anetration (en 6)
-27X-Blackboard-Expiration=1638176400000&X-Blackboard-Signature=WZUHUMegvo%2B0F 100% orua Suosiance q = Csxm X At (en 1) 4720 = -metal (eqn 2) now express heat flow in terms of Equation 1 for both the water and the metal, we get (Equation 3): q=CH20 X M20 X Atuzo = - metal X metal * Atmetar (eqn 3) 39F