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a) 43.08 g of CH14(g) (MW = 86.16 g mol-2) is burned in an excess of oxygen forming CO2(g) and H2O(l). Write the chemica
Posted: Thu Dec 02, 2021 5:14 am
by answerhappygod
- A 43 08 G Of Ch14 G Mw 86 16 G Mol 2 Is Burned In An Excess Of Oxygen Forming Co2 G And H2o L Write The Chemica 1 (69.72 KiB) Viewed 73 times
a) 43.08 g of CH14(g) (MW = 86.16 g mol-2) is burned in an excess of oxygen forming CO2(g) and H2O(l). Write the chemical equation for the combustion reaction that occurs, and then, using the data given below, determine AHⓇ and AU° for that reaction at 298.1 K. AH°m(298 K)/ kJ mol 1: C6H14(g) = -167.2 CO2(g) = -393.5 3/5 : H2O(1) = -285.8 b) For the reaction 2 CH3NH2(1) + CO2(g) → CH3CH2COOH(l) + N2(g) + H2(g) AH°m = -71.25 kJ mol; AS m = -348.9 J K mol-1 at 298 K. At 298 K will the reaction be spontaneous i) in an isolated system? ii) in a closed system? In each case explain your answer. c) You add 250 g of water at 26 °C from a foam coffee cup labelled 'A' into a second coffee cup, labelled 'B', containing 100 g of water at 95 °C. Assuming zero heat loss, what is the final temperature of the water in coffee cup B (Cwater = 4.184 J Kg)? 2