What quantity in moles of precipitate will be formed when 100.0 mL of 2.00 M Nal is reacted with 60.0 mL of 0.900 M Pb(N
Posted: Tue May 31, 2022 10:53 pm
What quantity in moles of precipitate will be formed when 100.0 mL of 2.00 M Nal is reacted with 60.0 mL of 0.900 M Pb(NO3)₂ in the following chemical reaction? 2 Nal(aq) + Pb(NO₂)₂(aq) → Pbl (s) + 2 NaNO₂(aq)